/*
   DemoOperators2.cpp
   CIS 150
   5/29/2008
   David Klick
   
   This program demonstrates type casting, simple math
   operators, and the results of integer division.
*/

#include <iostream>
using std::cin;
using std::cout;
using std::endl;

void cont();

int main()  {
   // declare and initialize variables
   int num1    = 0;
   int num2    = 0;
   int sum     = 0;
   int diff    = 0;
   int prod    = 0;
   int rem     = 0;
   int intQuot = 0;
   double quot = 0.0;
      
   // get input from user
   cout << "Enter two non-zero integers (separated by a blank): ";
   cin >> num1 >> num2;
   
   sum  = num1 + num2;
   diff = num1 - num2;
   prod = num1 * num2;
   intQuot = num1 / num2;
   rem = num1 % num2;
   // result is double since we cast one of the ints to a double
   quot = (double)num1 / num2;
  
   // display results
   cout << num1 << '+' << num2 << " is " << sum << '\n';
   cout << num1 << '-' << num2 << " is " << diff << '\n';
   cout << num1 << '*' << num2 << " is " << prod << '\n';
   cout << num1 << '/' << num2 << " is " << intQuot << '\n';
   cout << num1 << '/' << num2 << " is " << quot << " (num1 cast to be a double)\n";
   cout << num1 << '%' << num2 << " is " << rem << '\n';
   
   cont();
   return 0;
}

void cont() {
   if (cin.rdbuf()->sungetc() != -1 && cin.get() != '\n') cin.ignore(80,'\n');
   cout << "Press Enter to continue...";
   cin.get();
   return;
}

/*
   Sample output:
   
   Enter two non-zero integers: 5 2
   5+2 is 7
   5-2 is 3
   5*2 is 10
   5/2 is 2
   5/2 is 2.5 (num1 cast to be a double)
   5%2 is 1
*/